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Next: Exercise 8.1: Single-slit diffraction Up: Time dependent Schrödinger equation Previous: Time dependent Schrödinger equation

The time-evolution operator

The Schrödinger equation (81) can be integrated in a formal sense to obtain:

\begin{displaymath}
\psi(x,t)=U(t)\psi(x,t=0)=e^{-iHt}\psi(x,t=0).
\end{displaymath} (82)

From here we deduce that the wave function can be evolved forward in time by applying the time-evolution operator $U(t)=\exp{(-iHt)}$:

\begin{displaymath}
\psi(t+\Delta t)= e^{-iH\Delta t}\psi(t).
\end{displaymath}

Likewise, the inverse of the time-evolution operator moves the wave function back in time:

\begin{displaymath}
\psi(t-\Delta t)=e^{iH\Delta t}\psi(t),
\end{displaymath}

where we have use the property

\begin{displaymath}
U^{-1}(t)=U(-t).
\end{displaymath}

Although it would be nice to have an algorithm based on the direct application of $U$, it has been shown that this is not stable. Hence, we apply the following relation:

\begin{displaymath}
\psi(t+\Delta t)=\psi(t-\Delta t)+\left[e^{-iH\Delta t}-e^{iH\Delta
t}\right]\psi(t).
\end{displaymath}

Now, the derivatives with recpect to $x$ can be approximated by
$\displaystyle \frac{\partial \psi}{\partial t}$ $\textstyle \sim$ $\displaystyle \frac{\psi(x,t+\Delta t)-\psi(x, \Delta t)}{\Delta t},$ (83)
$\displaystyle \frac{\partial ^2 \psi}{\partial x^2}$ $\textstyle \sim$ $\displaystyle \frac{\psi(x+\Delta %
x,t)+\psi(x-\Delta x,t)-2\psi(x,t)}{(\Delta x)^2}.$ (84)

The time evolution operator is approximated by:
\begin{displaymath}
U(\Delta t)=e^{-iH\Delta t} \sim 1+iH\Delta t,
\end{displaymath} (85)

with an error of the order of $(\Delta t)^2$. Replacing the expression (82) for $H$, we obtain:


$\displaystyle \psi(x,t+\Delta t)= \psi(x,t-\Delta t)-2i[(4\alpha+\Delta t V(x))\psi(x,t)-$     (86)
$\displaystyle \alpha(\psi(x+\Delta x,t)+\psi(x-\Delta x,t))],$     (87)

with $\alpha=\frac{\Delta t}{2(\Delta x)^2}$.

The probability of finding an electron at $(x,t)$ is given by $\vert\psi(x,t)\vert^2$. This equations do no conserve this probability exactly, but the error is of the order of $(\Delta t)^2$. The convergence can be determined by using smaller steps.



Subsections
next up previous
Next: Exercise 8.1: Single-slit diffraction Up: Time dependent Schrödinger equation Previous: Time dependent Schrödinger equation
Adrian E. Feiguin 2004-06-01